I search a way to get the top X of values from timeseries influxdb2:
In this example, the top 2 of hdd_id Read_IOPS busiest.
CSV imported:
the granularity is one minute for each values/fields
the csv have a lot of hdd_ids and servers.
#datatype measurement,tag,tag,double,double,double,dateTime:number
HDD,server,hdd_id,Read_IOPS,Write_IOPS,Read_ms,time
HDD,srv1,hdd1,35,33,1,1671233940
HDD,srv1,hdd1,24,69,1,1671234000
HDD,srv1,hdd1,97,57,2,1671234060
HDD,srv1,hdd1,30,78,2,1671234120
HDD,srv1,hdd1,53,83,2,1671234180
HDD,srv1,hdd1,56,85,2,1671234240
HDD,srv1,hdd1,32,25,22,1671234300
HDD,srv1,hdd1,29,89,6,1671234360
HDD,srv1,hdd1,33,41,1,1671234420
HDD,srv1,hdd1,22,15,8,1671234480
HDD,srv1,hdd1,24,95,4,1671234540
…
HDD,srv1,hdd2,35,33,1,1671233940
HDD,srv1,hdd2,24,69,1,1671234000
HDD,srv1,hdd2,97,57,2,1671234060
HDD,srv1,hdd2,30,78,2,1671234120
HDD,srv1,hdd2,53,83,2,1671234180
HDD,srv1,hdd2,56,85,2,1671234240
HDD,srv1,hdd2,32,25,22,1671234300
HDD,srv1,hdd2,29,89,6,1671234360
HDD,srv1,hdd2,33,41,1,1671234420
HDD,srv1,hdd2,22,15,8,1671234480
HDD,srv1,hdd2,24,95,4,1671234540
…
HDD,srv1,hdd3,35,33,1,1671233940
HDD,srv1,hdd3,24,69,1,1671234000
HDD,srv1,hdd3,97,57,2,1671234060
HDD,srv1,hdd3,30,78,2,1671234120
HDD,srv1,hdd3,53,83,2,1671234180
HDD,srv1,hdd3,56,85,2,1671234240
HDD,srv1,hdd3,32,25,22,1671234300
HDD,srv1,hdd3,29,89,6,1671234360
HDD,srv1,hdd3,33,41,1,1671234420
HDD,srv1,hdd3,22,15,8,1671234480
HDD,srv1,hdd3,24,95,4,1671234540
…
I try with this query (flux influxdb2):
import "strings"
|> from(bucket: v.bucket)
|> range(start: v.timeRangeStart, stop: v.timeRangeStop)
|> filter(fn: (r) => r._measurement == “HDD”)
|> drop(columns: [“server”])
|> filter(fn: (r) => r._field == “HDD_Read_IOPS”)
|> map(fn: (r) => ({r with newhddid: strings.substring(v: r.hdd_id, start: 0, end: 4)}))
|> highestMax(n: 2, groupColumns: [“newhddid”])
|> aggregateWindow(column: “_value”, every: v.windowPeriod, fn: mean)
I search to display the 2 most busiest hdd_id about the Read_IOPS in grafana dashboard
I hope you can understand what i want to do.
Many thanks for any help.