Hello All,
I just try to build up graphics to see weekly average of license usages.
Average have to be collected weekly based only from business time.
Time: 7 - 17
Days: Monday to Friday
This is query to be used :
flexlm_feature_used{app=“app1”,name=“CAM5X”} → License usage
flexlm_feature_issued{app=“app1”,name=“CAM5X”} → Total amount of license
Can some one help me with this topic, thanks!
Hi, if I understand correctly, you want to calculate the average over the last week (7 days) limited to the business time, right?
What you could do is:
- Limit the result series to business time like:
<base query> and hour(time()) > 7 and hour(time()) < 17 and day_of_week(time()) >= 1 and day_of_week(time()) <= 5
(probably need to adjust the time for time zone)
- Calculate
avg_over_time
of the expression above, e.g.
avg_over_time((<base query> and hour(time()) > 7 and hour(time()) < 17 and day_of_week(time()) >= 1 and day_of_week(time()) <= 5)[7d:1h])
And use it as instant query - the returned value will be the average over last 7 days. I think it should work but I don’t have any data to test it out.
Hi,
Thanks!
Still some problem, also some other fine tuning needed to get some results.
When I take license usage from one week, between 5-15. Average is 49,64%.
sum(flexlm_feature_used_users{app=“app1”, name=“CAM5X”}
and on() (hour(vector(time())) >= 5 and hour(vector(time())) <= 15)
and on() (day_of_week(vector(time())) >= 1 and day_of_week(vector(time())) <= 5))
Below query return 51,5 %.
I don’t know where differences comes.
avg_over_time(
(
flexlm_feature_used{app=“app1”,name=“CAM5X”}
and on() (hour(vector(time())) >= 5 and hour(vector(time())) <= 15)
and on() (day_of_week(vector(time())) >= 1 and day_of_week(vector(time())) <= 5)
)[1w:30m]
)
Well, for starters you’ve used two different metrics in each query, which might give different results. Also, sum
and avg_over_time
are two different entities - sum
is an aggregation that summarizes each time series into one, one timestamp at a time. avg_over_time
calculates mean over provided time period with given resolution.
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