I have a MYSQL query that is referenced to a template variable. When the variable returns null, the mysql query fails since the IN clause contains an empty list. How do we handle such a scenario.
You can write CASE statement in your query .
Actually you cannot use CASE - Grafana does direct substitution on template variables. If no values are returned from variables, it ll be blank. So CASE or COALESCE can’t be used in this situation.