# Response time broken down by request

**URL:** <https://community.grafana.com/t/response-time-broken-down-by-request/97810>\
**Category:** Community Lounge\
**Created:** [November 17, 2022, 3:49pm UTC](https://community.grafana.com/t/response-time-broken-down-by-request/97810 "2022-11-17T15:49:33Z")\
**Posts on this page:** 2\
**Page:** 1

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**Author:** ![jbattsek](https://avatars.discourse-cdn.com/v4/letter/j/bbce88/32.png) [@jbattsek](https://community.grafana.com/u/jbattsek)\
**Post date:** [November 17, 2022, 3:49pm UTC](https://community.grafana.com/t/response-time-broken-down-by-request/97810/1 "2022-11-17T15:49:33Z")

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Hi! I’m new to k6 and am trying to test out a basic use case, but would like to make sure I have the right tool.

I’d like to write a script that

- Logs in to my app (request 1)

- then hit’s an api endpoint (request 2)

I’d like to run this script concurrently X times for N users.  
I’d like to determine average and 95%ile response times for request 1 and for request 2.

Is this possible? In looking at sample and test script outputs, I do not see a way to break it down by request. I also do not see how to determine how many times each request was hit in the time period of running the script.  
Thank you for any response!

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**Author:** ![olegbespalov](https://sea2.discourse-cdn.com/grafana/user_avatar/community.grafana.com/olegbespalov/32/36739_2.png) [@olegbespalov](https://community.grafana.com/u/olegbespalov)\
**Post date:** [November 23, 2022, 6:47am UTC](https://community.grafana.com/t/response-time-broken-down-by-request/97810/3 "2022-11-23T06:47:43Z")

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Hi @jbattsek !

Sorry for the long reply, and welcome to the community forums! 👋

For sure, it’s possible 😉

By default, the output doesn’t show you the per-request breakdown. However, a common workaround is to use tags & thresholds (See an example in this post [Graphql test serveral stages and every stage have multiple request - #3 by olegbespalov](https://community.grafana.com/t/graphql-test-serveral-stages-and-every-stage-have-multiple-request/98858/3)).

Let me know if that helps  
Cheers!
