hey guys, when I use __VU in code, K6 always throws SyntaxError when compile the script. Debuged for many times, can not find the cause of the error. Is it because __VU is used inappropriately in script? Anyone can tell me the reason for the error? [1] [2]

The error is exactly where the > and ^ symbols indicate it is :sweat_smile: You cannot just declare const something;, you need to assign some value to the constant when you create it, e.g. const foo = 'bar';, see const - JavaScript | MDN Use the var or let if you want to declare a variable early an…

Please read through the links in my previous post, specifically const - JavaScript | MDN const means it’s constant, that’s the whole point… value of a constant can’t be changed through reassignment (i.e. by using the assignment operator ), and it can’t be redeclared

Sorry @ned , I’m not very familiar with JS, if i set the variables to let type, how to reference variables in get_body function. [image]

I have no idea what you are trying to do here… :confused: But if you assign values to these variables only in some VUs (because of the if (__VU == 0), if (__VU == 1), etc. conditions), then it’s expected that they will not have value in the other VUs. Every VU will execute your script code independ…

Sorry for the late reply @ned ，I solved the problem successfully，thanks your pointer.

If (__VU == 0) { at <internal/k6/compiler/lib/babel.min.js>:2:28536(105)

Grafana k6

sunnini July 15, 2022, 10:56am 3

After declaring variables, k6 throwed TypeError: Assignment to constant variable.

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If (__VU == 0) { at <internal/k6/compiler/lib/babel.min.js>:2:28536(105)

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